The vertices of AABC are A(-6, -7), B(-3,-10) and
C(-5,2). Find the vertices of AA'B'C'. given the
translation rule below.
(x, y) (x - 2. y - 7)
a A (-8, -14), B (-5, -17), C'(-7,-5)
b
A'(-6, -12), B' (-6, -18).C'(-9, -12)
C A'(-12, -16), B(-10, -17), C'(-6, -5)
d
A'(-9, -20), B'(-6, -12). C'(-8, 8)

A, but try the rest of the points!

Step-by-step explanation:

I assume AABC means triangle ABC

Just do the operation to each point.  so A is (-6, -7)  (x - 2. y - 7) is telling you subtract 2 from -6 and 7 from -7 or in other words it changes from  (-6, -7)  to (-6 - 2. -7 - 7) = (-8, -14)

Only one answer has that point for A', but you should really really really try the rest.

dalila is incorrect. the whisker on the left is very long, going all the way out to 5. the whisker goes from 5 to 30, so it has a spread of 25. the rest of the box plot values are closer together, so 5 is an outlier

sinn is the total amount of students now and m were the students before, you subtract them both (n-m) and divide that by m. then, since to get a percentage from a fraction you have to multiply by 100, your answer should look like this: n-m/m*100

step-by-step explanation: