C) In the 1918 season, Babe Ruth had 26 doubles, 11 triples, and 11 home runs out of 95 base hits. How many singles did Babe Ruth get in the 1918 season?

Babe Ruth got 47 singles in the 1918 season.

Step-by-step explanation:

Outcomes for base hits.  =  singles, doubles , triples , home runs

Now , the number of singles = Number of base hits - Number of doubles -  Number of triples - Number of home runs

Given : Babe Ruth had 26 doubles, 11 triples, and 11 home runs out of 95 base hits.

Number of singles = 95-26-11-11

= 95 - 48

= 47

Hence, Babe Ruth got 47 singles in the 1918 season.

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."