A rocket is launched from the ground. The quadratic function y=-16x2+56x models the rockets height in feet above the ground after x seconds. About how long is the rocket in the air

Therefore,

3.5 s long was the rocket in the air.

Step-by-step explanation:

Given:

A rocket is launched from the ground.

Height function for Rocket is given as

Where,

y = height in function with x as time in second

To Find:

How long is the rocket in the air, x =?

Solution:

Expression is given

So for time in air put y = 0 in above Expression

x cannot be negative

∴ x = 3.5 sec.

Therefore,

3.5 s long was the rocket in the air.

use distributive property on all like terms and change your signs if you have a double negative or if you have positive/negative

the answer is a) y= 2 csc [0.5 (x+pi/2)]-1

step-by-step explanation: