Which of the following functions is graphed below hellppp

The correct answer is option C.

Step-by-step explanation:

In order to determine the equation of the function, whose graph is given to us in the question, we can use the various coordinates points and the points of discontinuities. Also, we can see the type of graph, for example, a parabolic, straight line etc.

Now, in the graph given in the question, we can see that from x<1, the graph is parabolic given by   and also we can see that x=1 is the discontinuous point, so we will not take x=1 in the domain of the function.

Now when , we have the straight line that is given by

where the curve is defined for x=1 also.

So, we will have the step-wise function whose equation will be given by option C.

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3