Two adjacent sides of a parallelogram have length of 5 cm and 11 cm. Each of the two diagonals divide the parallelogram into two congruent triangles. If the lengths of the diagonals are the smallest and the greatest possible prime values (as sides of the triangles), then what is the sum of the lengths of the diagonals ?

20 cm

Step-by-step explanation:

Since the diagonals have to be prime numbers, and they have to be able to be sides of a triangle, the formula would be 6<x<16. The prime numbers in this group are 7, 11, and 13. Since 7 is the smallest prime number in this group and 13 is the largest, 7+13=20.

the figures below are made out of circles, semicircles, quarter … find the area and the perimeter of each figure and give your answers as a completely simplified exact value in terms of π (no approximations). remember that we'll also have to cut whatever areas we get in half, since we're only dealing

step-by-step explanation:

the answer is simply just 6n add the two together as they have an n