Jonathon and Samantha row their canoe 28 miles downstream in 2 hours. After a picnic, they row back upstream. After 3 hours they only travel 12 miles. Assuming that they canoe at a constant rate and the river's current is constant, find the speed at which Jonathon and Samantha can row in still water.

the speed at which Jonathon and Samantha can row in still water is 9 mph

Step-by-step explanation:

Let x represent the speed of the canoe in still water.

Let y represent the speed of the river's current.

Jonathon and Samantha row their canoe 28 miles downstream in 2 hours. Assuming they rowed with the current, the total speed would be (x + y) mph

Distance = speed × time

Distance travelled downstream is expressed as

28 = 2(x + y)

Dividing through by 2, it becomes

14 = x + y - - - - - - - -1

After a picnic, they row back upstream. After 3 hours they only travel 12 miles. Assuming they rowed against the current, the total speed would be (x - y) mph

Distance travelled upstream is expressed as

12 = 3(x - y)

Dividing through by 3, it becomes

4 = x - y - - - - - - - -2

Adding equation 1 and equation 2, it becomes

18 = 2y

y = 18/2

y = 9 mph

it would more likely be bald eagle because its has more in the box so about 75%.

step-by-step explanation:

i dont get the question

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