How to expand (5x−6)^2

(5x-6)²=25x²-60x+36

Step-by-step explanation:

We use: (a-b)²=a²-2ab+b².

Thus we get

(5x-6)²=25x²-60x+36

Expand((5⋅x−6)2)

=62+2⋅(−6⋅5⋅x)+(5⋅x)2

=36−60⋅x+25⋅x2

the solution of the equation is 2.23 ⇒ answer b

step-by-step explanation:

* lets revise the meaning of exponential function

- the form of the exponential function is y = ab^x, where a ≠ 0, b > 0 ,  

  b ≠ 1, and x is any real number

- it has a constant base b

- it has a variable exponent x

- to solve an exponential equation, take the log or ln of both sides,  

  and solve for the variable

* lets solve the problem

∵

- the base is 7 and the exponent is x

- insert ㏑ in both sides

∴

- use the rule

∴ x ㏑(7) = ㏑(77)

- to find x divide both sides by ㏑(7)

∴

* the solution of the equation is 2.23 to the nearest 2 decimal places

a

step-by-step explanation: