Write a system of equations with 4,-5 as its solution

x + 2y  =6

3x + 4y = -8

Step-by-step explanation:

I would start by choosing my coefficients for the 2 equations. I will choose 1 and 2 for the first equation and 3 and 4 for the second equation.

1x + 2y = ?

3x + 4y = ?

Now I need to figure what in on the right-hand side, so I would substitute in 4 for x and -5 for y.

1(4) + 2(-5) = 4 - 10 = -6, so my first equation would be x + 2y = -6

3(4) + 4(-5) = 12 - 20 = -8, and my second equation is 3x + 4y = -8

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

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