Suppose that the duration of a routine doctor's visit is known to be normally distributed with a mean of 21 minutes and a standard deviation of seven minutes. If one of the visits is randomly chosen, what is the probability that it lasted at least 24 minute?

33.36% probability that it lasted at least 24 minutes

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean and standard deviation , the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

If one of the visits is randomly chosen, what is the probability that it lasted at least 24 minute?

This is 1 subtracted by the pvalue of Z when X = 24. So

has a pvalue of 0.6664

1 - 0.6664 = 0.3336

33.36% probability that it lasted at least 24 minutes

all the angles opposite to the angle 150 would be 150 and all the angles that are next to 150 are 30 because they equal 180 it you add it up.

step-by-step explanation: