(1 point) The series ∑Cn(x+4)n converges at x=0 and diverges at x=−11. Based on this information we know something about how big and small the radius of convergence R of the power series can be. Between what two values must R lie?

Following are the calculation of the value that lie on R:

Given:

converges at

diverges at

To find:

Find the value of R that lie=?

Solution:

When

When

So,

Therefore, the answer is "".

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R must lie between the two values 4 and 7

R ∈ (4,7)

Step-by-step explanation:

∑

converges at x= 0 and Diverges at x= -11

Given series is centered at x= -4

since the series converges at x= 0, which is a distance of 4 from x= -4

=> the radius of convergence (R) is at least 4

since the series diverges at x= -11, which is a distance of 7 from x= -4

=> the radius of convergence (R) cannot be more than 7

=> 4 ≤ R ≤ 9 ⇒ R ∈ (4,7)

the answer to question 1 is -8, 28.

step-by-step explanation:

area of rectangle a is 2 times that of rectangle b that means 2x+x =   36cm^2

3x = 36cm ^2

x = 36/3

x= 12cm^2

and 2x = 24cm^2

now side of square = are divided by sides = 36/4 = 6cm

that means length of rectangle a and b is 6cm too

now for rectangle a,

l*b = area

= 6*y=24

y=24/6 = 4

therefore dimensions of rectangle a are- length = 6cm, breadth = 4cm

and for rectangle b, length = 6cm and breadth = 6-4 = 2cm.

hope this .