What is the equation of a line l that has an x-intercept of (5, 0) and is perpendicular to another line m that has a slope -5?

Question 14 options:

A. y = 1/5 x + 5
B. y= -5x + 5
C. y = -5x+ 25
D. y = 1/5 x - 1

D. y = 1/5 x - 1

Step-by-step explanation:

The equation of a straight line can be represented in the slope intercept form as

y = mx + c

Where

c represents the y intercept

m represents the slope of the line

The slope of the given line m is - 5

If two lines are perpendicular, it means that the slope of one line is the negative reciprocal of the slope of the other line.

Therefore, the slope of the line, I passing through (5, 0) is 1/5

To determine the y intercept, we would substitute m = 1/5, x = 5 and y = 0 into y = mx + c. It becomes

0 = 1/5 × 5 + c

0 = 1 + c

c = 0 - 1

c = - 1

The equation becomes

y = x/5 - 1

1. 3.4/4

2. 0.8/7

3. 0.5 x 3

4. 0.9 x 6

5. 10.8

6. 2.35

7. 0.567

8. 9.35

9. 0.02

10. 0.06

11. 0.16

12. 0.42

13. 0.63

14. 5.6

15. 8.1

16. 9.9

17. 0.28

18. 0.48

19. 0.27

20. 0.49

21. 0.45

22. 0.72

23. 0.9

24. 0.88

25. 0.75

26. 0.16

27. 0.328

28. 0.495

29. 0.72

30. 1.068

a=24; b=12

step-by-step explanation:

a/b=2: 1

a=2b

36/(1+2)=12

b=12

a=24