Suppose you just received a shipment of eight televisions. Three of the televisions are defective. If two televisions are randomly selected, compute the probability that both televisions work. What is the probability at least one of the two televisions does not work?

The probability that both televisions work is

The probability at least one of the two televisions does not work is .

Step-by-step explanation:

Given : Number of televisions received = 8

Number of defective televisions=3

Number of good television = 8-3=  5

Then , the number of ways to select any two television out of 8 =

The number of ways to select two working televisions out of three =

Now ,  If two televisions are randomly selected, the the probability that both televisions work

Hence, the probability that both televisions work is

Also , the probability at least one of the two televisions does not work = 1- P( both televisions work)

Hence, the probability at least one of the two televisions does not work is

use this formula:

p(a\b) = p(a and b)/p(b).

take it from here.

sorry i need the points

step-by-step explanation:

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