A test preparation claims that more than 50% of the students who take their test prep course improve their scores by at least 10 points. Instead of advertising the percentage of customers who improve by at least 10 points, a manager suggests testing whether the mean score improves at all. For each customer they record the difference in score before and after taking the course (AfterminusBefore). a) State the null and alternative hypotheses. b) The P-value from the test is 0.65. Does this provide any evidence that their course works? c) From part b, what can you tell, if anything, about the mean difference in the sample scores? a) State the hypotheses.

If the mean score on a creativity test is 20, the standard deviation is 5, and the distribution is normal, the percentage of people who would obtain scores between 15 and 25 is a) 34% b) 14% + 34%= 48% c) 50% d) 34% + 34%= 68%

Step-by-step explanation:

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students in a class take a test and the mean score is 95 and the standard deviation is 8. If the lowest possible score to pass the test is 72, what percentage of students did not p Algebra -> Average -> SOLUTION: Students in a class take a test and the mean score is 95 and the standard deviation is 8.

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

x-150=475   x=625

step-by-step explanation:

if the bike after the sale ($150) is $475 then just simply add 150 to 475.