Find an equation for the line that passes through the point (-4, 10) and (16, -2)

y = 3/5x + 62/5

Step-by-step explanation:

Equation of a line with two points is

m = y - y_1 / x - x _1

m = y_2 - y_1 / x_2 - x _1

Equating both

y - y_1 / x - x_1 = y_2 - y_1 / x_2 - x_1

Using what we are provided with

(-4 , 10)(16 , -2)

x_1 = -4

y_1 = 40

x_2 = 16

y_2 = -2

Imputing the values

10 - (-2) / 16 - (-4) = y - 10 / x - (-4)

10 + 2 /16 + 4 = y - 10 / x + 4

12 / 20 = y - 10 / x + 4

Lets cross multiply

12 ( x + 4) = 20(y - 10)

Open the brackets

12x + 48 = 20y - 200

12x + 48 + 200 = 20y

12x + 248 = 20y

Following this equation of line

y = mx + C

20y = 12x + 248

Let's divide through by 20 to get y.

20y / 20 = 12x + 248 / 20

y = 12x + 248 / 20

We can separate it by

y = 12x / 20 + 248 / 20

y = 3/5x + 62/5

Therefore, the equation of the line is

y = 3/5x + 62/5