An object is launched at 9.8 meters per second from 73.5 meter tall platform. The objects height s (in meters) after t seconds I’d given by the equation s(t)= -4.9t2-9.8+73.5. Use the factoring to determine when the object hits the ground

The object hits the ground in 5 seconds.

Step-by-step explanation:

Given : An object is launched at 9.8 meters per second from 73.5 meter tall platform. The objects height s (in meters) after t seconds I’d given by the equation .

To find : Use the factoring to determine when the object hits the ground ?

Solution :

When the object hits the ground the distance is zero.

i.e. s(t)=0

So,

Applying quadratic formula,

Here, a=-4.9, b=-9.8 and c=73.5

Reject t=-3

Therefore, the object hits the ground in 5 seconds.

step-by-step explanation:

first you will have to convert 3/4 into a decimal

which is .75

then you will have to divide 1.5 by .75

which is 2

no you have to divide