Which of the following quadratic equations has the solution set {3,-5}

You can create the equation by multiplying (x-3) * (x +5)

x^2 +2x -15 = 0

As for the answers: The first AND the last equations are the answer.

Step-by-step explanation:

the equations are

x² + 2x - 15 = 0

x² + 2x + 20 = 35

(x + 5)(x - 3) = 0

Step-by-step explanation:

To determine the quadratic equations that has the solution set {3,-5}, we would substitute x = 3 or

x = - 5 into each equation.

1) x² + 2x - 15 = 0

For x = 3,

3² + 2 × 3 - 15 = 0

9 + 6 - 15 = 0

0 = 0

For x = - 5,

- 5² + 2 × - 5 - 15 = 0

25 - 10 - 15 = 0

0 = 0

(3, 5) is a solution

2) x² - 2x + 10 = - 5

For x = 3,

3² - 2 × 3 + 10 = - 5

9 - 6 + 10 = - 5

13 = - 5

It is not equal equal. So, (3, - 5) is not a solution

3) x² + 2x + 20 = 35

For x = 3

3² + 2 × 3 + 20 = 35

9 + 6 + 20 = 35

35 = 35

For x = - 5

- 5² + 2 × - 5 + 20 = 35

25 - 10 + 20 = 35

35 = 35

(3, 5) is a solution

4) (x - 5)(x + 3) = 0

For x = 3

(3 - 5)(3 + 3) = 0

- 2 × 6 = 0

- 12 = 0

It is not equal equal. So, (3, - 5) is not a solution.

5) (x + 5)(x - 3) = 0

For x = 3

(3 + 5)(3 - 3) = 0

0 = 0

For x = - 5,

(- 5 + 5)(- 5 - 3) = 0

0 = 0

(3, 5) is a solution

341

step-by-step explanation:

all you have to do is 9x31 (which equals 279) and then 20x31 (which equals 620). then you have to subtract. 620-279=341.