An independent-measures study produces sample means of M 1 = 20 and M 2 = 17. If both samples have n = 18 scores and Cohen’s d = 0.50, what is the value for the pooled variance?

Pooled variance =6

Step-by-step explanation:

Cohen's d is usually used in metal analysis. The formular for Cohen's d is given by:

Cohen's d= mean difference/ pooled variance.

Mathematically, it is written as:

Cohen's d =( M1 - M2) / S^2p

Where M1= mean for group 1

M2= mean for group 2

S^2p = pooled variance

Given:

M1= 20 , M2 = 17 and Cohen's d = 0.50

Pooled variance = ( M1 - M2)/ Cohen's d

Pooled variance = (20 - 17 ) / 0.5 = 3/0.5

Pooled variance = 6

$35.59 in pounds

step-by-step explanation:

32

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