The radius of the base of a cylinder is increasing at a rate of 777 millimeters per hour. The height of the cylinder is fixed at 1.51.51, point, 5 millimeters. At a certain instant, the radius is 121212 millimeters. What is the rate of change of the volume of the cylinder at that instant (in cubic millimeters per hour)

252π  or 791.7 mm³/h

Step-by-step explanation:

The volume of a cylinder is given by

We desire to find the volume rate, that is,

dr/dt is the rate of change of the radius which is 7 mm/h.

dV/dr is derived by differentiating the volume equation, yielding

At r = 12 mm and h = 1.5 mm,

i did it myself and i got 4.2 (b) hope its right

step-by-step explanation: