For what value of x is the double product of the binomials x+2 and x–2 is 16 less than the sum of their squares?

pls help I’m confused

for all values of x = 2 is the double product of the  binomials x+2 and x–2 is 16 less than the sum of their squares

Step-by-step explanation:

By Using the difference of two square:

The product of the binomials:

Double the product yields =    ----- equation (1)

However, the sum of their squares can be expressed as follows:

16 less than that will be:

            ----------- equation (2)

NOW; the question says for what value of the "x" are those two equation equal to each other;

To tackle the problem; we equate equation (1) and equation (2) together.

So; now we can have:

  =

In this scenario; we found out that the left-hand side is equal to the right-hand side.

So;

We therefore conclude that for all values of x = 2 is the double product of the  binomials x+2 and x–2 is 16 less than the sum of their squares

Also, we can say that for all values of "x" = for all intervals or for set notations.

395.84

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