Find the angle between the given vectors to the nearest tenth of a degree.

u = <8, 7>, v = <9, 7>

-8.3°
1.7°
3.3°
13.3°

Step-by-step explanation:

If θ is the angle between two vectors u and v, then cosθ = (u·v) / [llull llvll]

     u·v = (8)(9) + (7)(7) = 121

     llull = √[(8)2 + (9)2] = √145      llvll = √[(7)2+(7)2] = 7√2

So, cosθ = 121/ [7√290]

            = 1.015052094

         θ = Cos-1(1.015052094) ≈ 3.3

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