Mathematics, 11.03.2020 23:12 alvfran1041
Misaka solved the radical equation x – 3 = but did not check her solutions. (x – 3)2 = x2 – 6x + 9 = 4x – 7 x2 – 10x + 16 = 0 (x – 2)(x – 8) = 0 x = 2 and x = 8 Which shows the true solution(s) to the radical equation x – 3 = ?
x = 2
x = 8
x = 2 and x = 8
There are no true solutions to the equation.
Answers: 1
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Misaka solved the radical equation x – 3 = but did not check her solutions. (x – 3)2 = x2 – 6x + 9 =...
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