Andrew has a total of one hundred forty-three pennies, nickels, and dimes. He has a total of $9.11. He has seventeen more nickels than pennies and sixteen more dimes than nickels. How many of each coin does he have?

he has 31 pennies, 48 nickels and 64 dimes

Step-by-step explanation:

The worth of a penny is 1 cent. Converting to dollars, it becomes

1/100 = $0.01

The worth of a dime is 10 cents. Converting to dollars, it becomes

10/100 = $0.1

The worth of a nickel is 5 cents. Converting to dollars, it becomes

5/100 = $0.05

Let x represent the number of pennies that he has.

Let y represent the number of nickels that he has.

Let z represent the number of dimes that he has.

Andrew has a total of one hundred forty-three pennies, nickels, and dimes. It means that

x + y + z = 143- - - - - - - - - - -1

He has a total of $9.11. It means that

0.01x + 0.05y + 0.1z = 9.11- - - - - - - 2

He has seventeen more nickels than pennies. It means that

y = x + 17

x = y - 17

He has sixteen more dimes than nickels. It means that

z = y + 16

Substituting x = y - 17 and z = y + 16 into equation 1, it becomes

y - 17 + y + y + 16 = 143

3y - 1 = 143

3y = 143 + 1 = 144

y = 144/3

y = 48

x = y - 17 = 48 - 17

x = 31

z = y + 16 = 48 + 16

z = 64

answer is the third choice:

3x^5+4x^4+x^3+2x^2-10x-7=0

step-by-step explanation: