How does the volume of a cone change when the radius is quadrupled and the height id reduced to 1/5 of the original size?

The volume (V) of the cone is one-third of the product of its height (h) and area (A). 
                                    V = A x h = πr²h 
Now, if the radius is quadrupled and the height is reduced to 1/5, the equation will be,
                                  V2 = π(4r)²(1/5 h) = π(3.2)r²h
Thus, the second volume would be 3.2 time the first volume.