The voltage in an electrical circuit is multiplied by itself each time it is reduced. The voltage is 27/125 of a volt and it has been reduced 3 times. Write the voltage in exponential form. What was the original voltage in the circuit.

The voltage in exponential form would be .

The original voltage in the circuit is of a volt.

Step-by-step explanation:

Let x represent the original voltage.

We have been given that the voltage in an electrical circuit is multiplied by itself each time it is reduced. The voltage is 27/125 of a volt and it has been reduced 3 times.

The original voltage multiplied by itself for 3 times would be .

Now, we will equate with 27/125 as:

We know that 27 is cube of 3 and 125 is cube of 5, so we can represent our equation as:

Therefore, the voltage in exponential form would be

Now, we will take cube root of both sides to find original voltage in the circuit as:

Using property , we will get:

Therefore, the original voltage in the circuit is of a volt.

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answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

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