The density of a fish tank is 0.3fish over feet cubed. there are 15 fish in the tank. what is the volume of the tank?

5 ft3

45 ft3

50 ft3

90 ft3

The population density (d) of the fish in the tank is the number of fishes (n) in a given volume (v) 
                                        d = n / v
The volume is the quotient when n is divided by d. Substituting the known values,
                                 v = n / d  = 15 fish / 0.3 fish over ft³
Thus, the volume of the tank is 50 ft³.

Answer:

$4034.40

step-by-step explanation:

the perimeter of the field is the sum of the lengths of the four sides:

47 yd + 158 yd + 47 yd + 158 yd = 410 yd

the cost of 3 ft (1 yd) of fence is 3×$3.28 = $9.84.

so the cost of jake's wood perimeter fance is

(410 yd) × ($9.84 /yd) = $4034.40

The 3rd quadrant as 3x+g5ti=56i: 92d-543