hi ! please help !

write (3 + 41) + (8 + 21) as a complex number in standard form.

A. 11 - 61
B. 11 + 61
C.5+ 121
D. 7 + 101

Hey there! I was looking at your question for a bit then realized you meant , the imaginary number, not "1" at the end of each number.

The expression we are given is:

Open parenthesis and combine like terms:

This is answer choice B (assuming it's supposed to be an and not a "1" at the end)

Let me know if you need any clarifications, thanks!

~ Padoru

option b

Step-by-step explanation:

a complex number is of the form a+bi

(3+4i)+(8+2i)

3+8+i(4+2)

11+6i

is the required answer

damm bro the struggle

step-by-step explanation:

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.