Mathematics, 11.03.2020 06:32 RedDemon59
Given line am=cp, line cm=gp, c is the midpoint of line ag prove triangle acm = triangle cgp
Answers: 2
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M∠aoc is a straight angle angle boc = 6x + 29 m∠boc=6x+29 angle aob = 3x + 124 m∠aob=3x+124 ∘ find angle boc
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Rewrite 9 log, x2 in a form that does not use exponents. 9log, x = log, x
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The areas of two similar triangles are 72dm2 and 50dm2. the sum of their perimeters is 226dm. what is the perimeter of each of these triangles?
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Afamily went out to dinner and their bill was $113.if they want to leave a 19% tip, how much should they leave.
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Given line am=cp, line cm=gp, c is the midpoint of line ag prove triangle acm = triangle cgp...
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