In a certain country, the true probability of a baby being a boy is 0.511. Among the next eight randomly selected births in the country, what is the probability that at least one of them is a girl?

The probability that at least one of 8 babies born is a girl  is 0.9954.

Step-by-step explanation:

Let X = a baby born is a girl.

The probability of a baby born being a girl is,

P (G) = 1 - P (B)

        = 1 - 0.511

     p  = 0.489

The number of births is, n = 8.

The random variable X follows a Binomial distribution with parameters n and p.

The probability mass function of the Binomial distribution is:

Compute the probability that out of 8 births at least one is a girl as follows:

P (X ≥ 1) = 1 - P (X < 1)

             = 1 - P (X = 0)

Thus, the probability that at least one of 8 babies born is a girl  is 0.9954.

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

answer: the anser is 3

step-by-step explanation:

c- 2o is equal to 9