Lots of 40 components each are deemed unacceptable if they contain 3 or more defectives. The procedure for sampling a lot is to select 5 components at random and to reject the lot if a defective is found. a) What is the probability that exactly 1 defective is found in the sample if there are 3 defectives in the entire lot? Find the mean and variance of the number of defective components in the selected 5 and then use Chebyshev's theorem to interpret the interval b) t 2

The probability of founding exactly one defective item in the sample is P=0.275.

The mean and variance of defective components in the sample are:

Step-by-step explanation:

In the case we have a lot with 3 defectives components, the proportion of defectives is:

a) The number of defectives components in the 5-components sample will follow a binomial distribution B(5,0.075).

The probability of having one defective in the sample is:

b) The mean and variance of defective components in the sample is:

The Chebyschev's inequality established:

alright well the answers to your question is

2xy/9 hope this have a nice day : )

step-by-step explanation: