A can in the shape of a cylinder has a diameter of 10 cm and a height of 6 cm. how much wrapping paper is needed to cover the cylinder in square centimeters ?

and I also need help with this question

The volume of the cylinder is _ lesser/greater than the volume of a cone, therefore the volume of the cone is ___ lesser / greater than the volume of a cylinder.

Step-by-step explanation:

To determine the amount of wrapping paper needed to cover the can, we would determine the total surface area of the cylindrical can. The formula for determining the total surface area of a cylinder is expressed as

Total surface area = 2πr² + 2πrh

Where

r represents the radius of the cylinder.

h represents the height of the cylinder.

π is a constant whose value is 3.14

From the information given,

Diameter = 10 cm

Radius = diameter/2 = 10/2

Radius = 5 cm

Height = 6 cm

Therefore,

Total surface area = (2 × 3.14 × 5²) + (2 × 3.14 × 5 × 6)

= 157 + 188.4 = 345.4 cm²

345 cm² of wrapping paper is needed to cover the cylinder.

2) Volume of cylinder = πr²h

Volume of cone = 1/3πr²h

3 × Volume of cone = πr²h

The volume of the cylinder is 3 times greater than the volume of the cone. Therefore, the volume of the cone is 1/3 times lesser than the volume if the cylinder.

5/6

step-by-step explanation:

if i remember correctly with perpendicular stuff you just take away the negative