PLEASE SOMEONE HELP AND SHOW UR WORK..
A prop for the theater club’s play is constructed as a cone topped with a half-sphere. What is the volume of the prop? Round your answer to the nearest tenth of a cubic cm. Use 3.14 to approximate pi, and make certain to show your work. Hint: you may need to find the volume of the component shapes.

The answer is 2,713 in³

The volume (V) of the prop is the sum of the volume of cone (V1) and half of the volume of the sphere (V2): V = V1 + 1/2 * V2

Volume of the cone is:

V1 = π r² h / 3

According to the image,

h = 14 in

r = 9 in

and

π = 3.14

V1 = 3.14 * 9² * 14 / 3 =  1,186.92 in³

The volume of the sphere is:

V2 = π r³ * 4/3

According to the image,

r = 9 in

and

π = 3.14

V2 = 3.14 * 9³ * 4/3 = 3,052.08 in³

The volume of the prop is:

V = V1 + 1/2 * V2

V = 1,186.92 in³ + 1/2 * 3,052.08 in³

V = 1,186.92 in³  + 1,526.04 in³ 

V = 2,712.96 in³ ≈ 2,713 in³

d. millimeters per hour.

step-by-step explanation:

we are given that,

carlo used a rain gauge to measure the amount of water his lawn is receiving from the sprinklers.

since, according to the options, we see that,

water cannot be measured by 'miles per hour', 'meters per second' and 'grams per seconds'.

we get that, the water can be measured by 'millimeters per hour'.

hence, the appropriate rate for describing the amount of water is 'millimeters per hour'.