A town has a population of 20000 and grows at 2.5% every year. To the nearest year, how long will it be until the population will reach 35300? Answer ASAP PLS

  23 years

Step-by-step explanation:

The equation for the exponential growth of the population can be written as ...

  population = (initial value)×(1 + (growth rate))^t

where t is the time period applicable to the growth rate. (Here, it is years.)

Filling in the given numbers, we have ...

  35300 = 20000×1.029^t

  35300/20000 = 1.029^t . . . . divide by 20,000

  log(353/200) = t×log(1.029) . . . . take logarithms

  log(353/200)/log(1.029) = t ≈ 23.01

It will be 23 years until the population reaches 35,300.

it will take 23 years.

Step-by-step explanation:

We would apply the formula for exponential growth which is expressed as

A = P(1 + r)^t

Where

A represents the population after t years.

t represents the number of years.

P represents the initial population.

r represents rate of growth.

From the information given,

P = 20000

A = 35300

r = 2.5% = 2.5/100 = 0.025

Therefore

35300 = 20000(1 + 0.025)^t

35300/20000 = (1.025)^t

1.765 = (1.025)^t

Taking log of both sides to base 10

Log 1.765 = log1.025^t = tlog1.025

0.247 = 0.0107t

t = 0.247/0.0107

t = 23 years

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

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