The function A(b) relates the area of a trapezoid with a given height of 10 and
one base length of 7 with the length of its other base.
It takes as input the other base value, and returns as output the area of the
trapezoid.
A(W= 10.577
Which equation below represents the inverse function B(a), which takes the
trapezoid's area as input and returns as output the length of the other base?

The function of the trapezoid area is:

A(x)=(B+b)*h/2

Where B and b are the bases and h is the height.

With the given data: h=10 B and b =7 and x (it may vary which one is bigger)

So that function becomes:

A(x)=(7+x)*10/2

A(x)=(7+x)*5

So if you want the inverse function, you have to operate to find x:

A(x)/5=7+x

A(x)/5-7=x

So the new function is:

x(A)=A/5-7

y/x of point b= y/x of point a

step-by-step explanation:

(i got the same question, this was the correct answer.)

1. 16.64

a^2+b^2=c^2

pr^2=pq^2+qr^2

pr^2=14^2+ 9^2

pr^2=196+81

pr= sqr root of 277

16.64

2. 11.31

c^2-a^2=b^2

18^2- 14^2=b^2

b^2=324-196

b=sqr root of 126

b=11.31

hope it ! (btw im in connections academy to, good luck! )