If f(x) = 3x + 2 and g(x) = x2 + 1, which expression is equivalent to (f circle g) (x)?
(3x + 2)(x 2 + 1)
3x 2 + 1 + 2
(3x + 2)2 + 1
3(x 2 + 1) + 2

(3x+2)^2+1

Step-by-step explanation:

(f°g)(x) =g(f(x)) =g(3x+2)=(3x+2)^2 +1

Choice D,  3 (x^2+1) + 2

Explenation:

f(g(x)) = f (x^2 + 1) = 3 * (x^2 +1) + 2 = (3 x^2 + 3) + 2                  

Factor 3 from each term:

(x^2 _1) + 2

which makes the answer choice "d".

its 60

4 x 12 = 48

3 x 4 = 12

48 + 12 = 60

yeeeet

the polynomial is a perfect square trinomial of the form a^2-2ab+b^2:

option a. true

step-by-step explanation:

9x^2-12x+4

comparing with the form a^2-2ab+b^2

1.) a^2=9x^2

solving for a: square root both sides of the equation:

sqrt(a^2)=sqrt(9x^2)

a=sqrt(9) sqrt(x^2)

a=3x

2.) b^2=4

solving for b: square root both sides of the equation:

sqrt(b^2)=sqrt(4)

b=2

to be a perfet square trinomial 2ab must be equal to 12x. let's check:

2ab = 2 (3x) (2)

2ab = 12x

correct