If someone throws a ball down from a height of 100 meters, the ball's distance from the ground can be modeled by the equation: d = − 9.8 t 2 − 15 t + 100 where t is the time in seconds and d is the distance in meters.

Question;

At what time (t) will the ball hit the ground?

The answer to the question is;

The ball will hit the ground at t = 2.52 s

Step-by-step explanation:

To answer the question we note the formula for distance from the gound is given by

d = − 9.8·t² − 15·t + 100

To find out the time when the ball hits the ground we have

The ball hits the ground at d = 0, therefore we have

0 = − 9.8·t² − 15·t + 100, solving by factorization gives

(t-2.52)(t+4.05)×(-9.8) = 0

Therefore the ball hits the ground at either 2.52 s or -4.05 s (imaginary)

Which gives t = 2.52 s.

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation:

answer: options?

step-by-step explanation: