Find two consecutive numbers whose squares, when subtracted, equals 43.
Please help this is due tomorrow and show work thank you☺️ I tried to figure it out but couldn’t

21 and 22

Step-by-step explanation:

let the 2 consecutive numbers be n and n + 1, then

(n + 1)² - n² = 43 ← expand (n + 1)² using FOIL

n² + 2n + 1 - n² = 43 ← collect like terms on left side

2n + 1 = 43 ( subtract 1 from both sides )

2n = 42 ( divide both sides by 2 )

n = 21

Thus the numbers are 21 and 22

21 and 22 are two consecutive numbers whose squares, when subtracted, equals 43.

Step-by-step explanation:

Let x, x+1 are two consecutive numbers

According to given Condition

21 and 22 are two consecutive numbers whose squares, when subtracted, equals 43.

alright well the answers to your question is

2xy/9 hope this have a nice day : )

step-by-step explanation:

i think the answer would be c