A baseball park has determined that the number of people contained in each vehicle parked in one of their lots has following distribution.
Number of People 1 2 3 4 more than 4
Probability 0.20 0.35 0.25 0.10 ?
a) What is the probability that more than 4 people arrive in a vehicle?

Pr(No. of people > 4) = 0.10

Step-by-step explanation:

The vehicle parking has the following probability distribution

Number of People 1 2 3 4 more than 4

Probability 0.20 0.35 0.25 0.10 ?

We want to find out the probability of number of people more than 4

No.of people = 1 -> Pr(1) = 0.20

No.of people = 2 -> Pr(2) = 0.35

No.of people = 3 -> Pr(3) = 0.25

No.of people = 3 -> Pr(4) = 0.10

Pr(No. of people > 4) = ?

We know that the sum of probabilities must be equal to 1

Pr(No. of people > 4) = 1 - Pr(1) - Pr(2) - Pr(3) - Pr(4)

Pr(No. of people > 4) = 1 - 0.20 - 0.35 - 0.25 - 0.10

Pr(No. of people > 4) = 1 - 0.90

Pr(No. of people > 4) = 0.10

Therefore, the probability that more than 4 people arrive in a vehicle is 0.10.

idk lol

step-by-step explanation: