Suppose u and v are differentiable functions of x and that

u(1) = 2, u'(1)= 0, v(1)= 5, v'(1)=-1

Find the values of the following derivatives at x =1

a) d/dx (uv)

b) d/dx(u/v)

c) d/dx (v/u)

d) d/dx (7v-2u)

B I personally think..

Step-by-step explanation:

Hi,

Use Differential Formula :

d(u(x) • v(x))/dx = u'(x) • v(x) + u(x) • v'(x)

at x = 1 :

d(u(1) • v(1))/dx = u'(1) • v(1) + u(1) • v'(1)

d(u(1) • v(1))/dx = -5 • 6 + 4  • -2

d(u(1) • v(1))/dx = -30 - 8

d(u(1) • v(1))/dx = -38

Hope this helped :)

i used to know how to do this in 7th but i forget easily

step-by-step explanation:

so far i think you have the right thing going for you just remember soh cah toh

step-by-step explanation:

sine over hypotenuse

cosine   equals adjacent

tangent over hypotenuse