Business rents in-line skates and bicycles to tourists on vacation. A pair of skates rents for $15 per day. A bicycle rents for $20 per day. On a certain day, the owner of the business has 25 rentals and takes in $450. Write a system of equation to represent this situation, then solve the system of equations to find the number of each item rented.

The number of skates rented are 10 and number of bicycle rented are 15.

Step-by-step explanation:

Given:

Business rents in-line skates and bicycles to tourists on vacation. A pair of skates rents for $15 per day. A bicycle rents for $20 per day. On a certain day, the owner of the business has 25 rentals and takes in $450.

Now, to find the number of each item rented.

Let the number of skates rented be

And let the number of bicycle rented be

So, the owner of the business has total rentals:

Now, the total amount it takes:

Substituting the value of from equation (1):

Subtracting both sides by 375 we get:

Dividing both sides by 5 we get:

The number of bicycles rented = 15.

Now, substitute the value of in equation (1):

The number of skates rented = 10.

Therefore, the number of skates rented are 10 and number of bicycle rented are 15.

the answer would be 150 books

step-by-step explanation:

if you divide 300 by 2 you will get 150

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)