A study of a population showed that males' body temperatures are approximately Normally distributed with a mean of 98.4 degrees Upper F98.4°F and a population standard deviation of 0.400.40degrees°F. What body temperature does a male have if he is at the 94 th94th percentile? Draw a well-labeled sketch to support your answer.

answer: y = -2.5x - 15

              (-6,0)

step-by-step explanation:

26 is 33.33% of 78

step-by-step explanation:

26 is what percent of 78?

26 is p% of 78

equation: y = p% * x

solving our equation for p

p% = y/x

p% = 26/78

p = 0.3333

convert decimal to percent:

p% = 0.3333 * 100 = 33.33%

can you complete your sentence? i could !