Mathematics, 10.03.2020 17:22 MarishaTucker

A jet lands on a runway at 110 m/s [forward]. When stopping, the jet can accelerate at 6.2 m/s2 [backward]. K/U T/I A (a) Calculate the minimum time for the jet to stop. [ans: 18 s] (b) What is the minimum safe length for this runway? [ans: 9.8 3 102 m] (c) Explain why the runway should be much longer than the minimum safe length.

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Answer from: assassin42

a) Minimum time for the jet to stop = 18 secs approximately

b) Minimum safe length for the runway = 975.6 m

c) The actual stopping distance would vary based on multiple factors like speed of the aircraft at the time of landing, weather conditions, change in friction due to wetness of the surface etc.. Hence the runway should be much longer than the minimum safe distance

Step-by-step explanation:

Step 1 :

Given,

Initial velocity of the jet = 110 m/s

Acceleration of the jet = - 6.2 m/s² [negative because its backward acceleration]

Final velocity = 0 [because the jet has to stop]

Step 2 :

The minimum time for the jet to stop can be computed using the formula

v = u + at

where v represents the final velocity = 0

u = initial velocity = 110

a = -6.2

Substituting,

110 - 6.2t = 0

t = -110 ÷ -6.2 = 17.74 secs which is approximately 18 secs

Step 3 :

The minimum safe length for this runway can be computed using the formula

s = ut + $\frac{1}{2}$ at²

where s is the distance.

Substituting ,

s= 110× 18 + $\frac{1}{2}$ (-6.2) ×18× 18

= 1980 - 1004.4 = 975.6 m

Step 4:

Answer :

a) Minimum time for the jet to stop = 18 secs approximately

b) Minimum safe length for the runway = 975.6 m

Answer from: Quest

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in $\delta bea$ and $\delta dea$ ;

$ba=da$ , as these are radii of our given circle.

$ea=ea$

therefore, $\delta bea\cong \delta dea$ by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

$3x-24=x+10$

$3x-x=24+10$

$2x=34$

$x=\frac{34}{2}$

$x=17$

now let us substitute x=17 in the expression for the length of be.

$\text{length of be}=3x-24$

$\text{length of be}=3\cdot 17-24$

$\text{length of be}=51-24$

$\text{length of be}=27$

therefore, length of be will be 27 units and option c is the correct choice.

In circle a, ∠bae ≅ ∠dae. what is the length of be? 14 units 17 units 27 units 34 units

Answer from: Quest

step-by-step explanation:

a and d

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A jet lands on a runway at 110 m/s [forward]. When stopping, the jet can accelerate at 6.2 m/s2 [bac...

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