(x+d)(x+e)=x^2+fx+33
In the equation above, d, e, and f are positive constants. Which of the following are possible integer values of f?
a) f= 0 or 1
b) f= 1 or 33
c) f= 2 or 16.5
d) f= 14 or 34

f=14 or f=34

Step-by-step explanation:

(x+d)(x+e) =x^2 +fx+33, d, e, f>0

x^2 +xe+dx+de=x^2+fx+33

x^2+(e+d)x+de=x^2 +fx+33 that

e+d=f and d*e=33, d=33/e

e+33/e=f

33=1*33 or 33=3*11

If e=1,d=33 then f=34

If e=3*,d=11, then f=14

the answer

b. they are parallel and will never intersect.

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18