Binh solved this system of equations by graphing. Line 1: y = negative one-half x minus three-halves. Line 2: y = x minus 3. Binh’s Graph On a coordinate plane, a line with equation y = x minus 3 goes through (negative 3, 0) and (0, 3). A line with equation y = negative one-half x minus three-halves goes through (negative 3, 0) and (1, negative 2). Binh says the point of intersection is (0, –3). Which statements identify the errors Binh made? Check all that apply.

Binh listed the coordinates in the wrong order when describing the point of intersection on his graph.
Binh should have graphed the y-intercept of y = x minus 3 at (0, negative 3).
Binh should have graphed the y-intercept of y = x minus 3 at (0, 1).
Binh should have graphed the y-intercept of y = negative one-half x minus three-halves at (0, negative one-half).
Binh should have found the point of intersection to be (1, negative 2).

Two of the statements apply:

Explanation:

1. Line 1

2. Line 2

3.  Binh’s Graph on a coordinate plane, a line with equation y = x - 3 goes through (- 3, 0) and (0, 3).

This is wrong because the point (-3, 0) is not on the line y = x - 3:

The other point, (0, 3) is wrong too

4. A line with equation y = -(1/2)x - (3/2) goes through (- 3, 0) and (1, -2).

Check the points:

Both points are correct

5. Binh says the point of intersection is (0, –3). Which statements identify the errors Binh made?

Binh listed the coordinates in the wrong order when describing the point of intersection on his graph?

Binh should have graphed the y-intercept of y = x - 3 at (0, - 3)?

Correct!

Binh should have graphed the y-intercept of y = x - 3 at (0, 1)?

Binh should have graphed the y-intercept of y = -(1/2)x -3/2 at (0, -1/2)?

No, this is wrong:

Binh should have found the point of intersection to be (1, - 2).

Correct!

Yes, the solution of the equation is (1, -2) and he should have found that intersection point. Proof:

Thus, the point of intersection is (1, -2).

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step-by-step explanation:

step-by-step explanation:

i found the life tables for the year 2012. 

life table of males at age 30. probability of dying between ages x and x+1

total population:  

29–30 . . . . . . . . . . . . 0.001030

30–31 . . . . . . . . . . . . 0.001061

males:  

29–30 . . . . . . . . . . . . 0.001420

30–31 . . . . . . . . . . . . 0.001448

white population

29–30 . . . . . . . . . . . . 0.001005

30–31 . . . . . . . . . . . . 0.001037

white males

29–30 . . . . . . . . . . . . 0.001372

30–31 . . . . . . . . . . . . 0.001399

non hispanic white population

29–30 . . . . . . . . . . . . 0.001083

30–31 . . . . . . . . . . . . 0.001116

non hispanic white males

29–30 . . . . . . . . . . . . 0.001477

30–31 . . . . . . . . . . . . 0.001503

jacob, non hispanic white male. 30 years old.

probability that jacob lives to be 30 years old. 

since the given probabilities are probabilities of dying, i think we simply subtract it from 1 to get the probability of living. we will use the probability of non hispanic white male.

                                          probability of living to be 30 y.o.

29 - 30 : 1 - 0.001477 = 0.998523

30 - 31 : 1 - 0.001503 = 0.998497