The value stored in variable s at the end of the execution of the loop could best be described as . Assume that all variables are of type int. z = 0; g = 0; s = 0; i = 0; while (i < 50) { scanf("%d", &t); s = s + t; if (t >= 0) g = g + 1; else z = z + 1; i = i + 1; }

It will describe the sum of the numbers scanned.

As we can see whatever you scan or take input it will be added to s without any condition. So at the end, sum of all scanned number will be save in variable s

step by step solution :

step   1   :

1.1     4 = 22

(4)3 = (22)3 = 26

equation at the end of step   1   :

  ((23) • 26)2

step   2   :

equation at the end of step   2   :

  (23 • 26)2

step   3   :

final result :

  218

ya

the answer is -6

step-by-step explanation:

the answer is -6 because its next to the variable m