At the district competition for 5th grade jump-roper of the year, the following number of jumps without stopping were recorded per student:
203,245,237,233,90,100,100,277,265, 264,265,285,288,291,
291,290,300,224,200,257,290,279,266 ,288
What is the mean number of jumps, rounded to the nearest hundredth?
What is the median number of jumps?

Mean = 242.83

Median = 265

Step-by-step explanation:

Looking at the data set, we see there are "24" numbers.

The mean is the average, which is sum of all the numbers divided by the number of numbers.

The median is the middle value when the numbers are arranged in ascending order. Since there are even number of numbers (24), the median would be the average of 12th number and 13th number.

First, lets arrange the numbers in ascending order:

90, 100, 100, 200, 203, 224, 233, 237, 245, 257, 264, 265, 265, 266, 277, 279, 285, 288, 290, 290, 291, 291, 300

The mean is the sum of all of them divided by 24:

Mean = 242.83

The median is the average of 12th number (265) and 13th number (265). So that is:

(265+265)/2 = 265

Thus,

Mean = 242.83

Median = 265

4444444444444 i think

according to egenuity the answer is

step-by-step explanation:

d. 344.22