1. A sequence has a second term of -8 and a common difference of 5.
The sixth term of the sequence is .

A. 7
B. -3
C. -28
D. 12

2. Which of the following expressions would give a sequence with a first term of -4 and a common difference of 3?

A. 3n – 7
B. 3n – 4
C. -4n + 3
D. -4n + 2

3. If n is a term of the sequence 14, 8, 2, -4, …, which expression would you give the value of n?

A. -6n + 14
B. -4n + 18
C. 3n + 11
D. -6n + 20

4. The fifteenth term of the sequence 14, 8, 2, -4, … is .

A. -110
B. -90
C. -70
D. -76

A1. 12 i.e option D

A2. 3n-7 i.e option A

A3. -6n+20 i.e option D

A4. -70 i.e option C

Step-by-step explanation:

aₙ = a₁ + (n - 1) × d  

aₙ=the nᵗʰ term in the sequence

a₁=the first term in the sequence

d=the common difference between terms

Using the above formula to solve the first part, we have :

For the second part, we have :

For the third part, we have :

For the fourth part, we have :

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl