An oil exploration company currently has two active projects, one in Asia and the other in Europe. Let A be the event that the European project is successful and B be the event that the Asian project is successful. Suppose that A and B are independent events with P(A) = 0.6 and P(B) = 0.2.

(a) If the Asian project is not successful, what is the probability that the European project is also not successful? Explain your reasoning.
(b) What is the probability that at least one of the two projects will be successful?
(c) Given that at least one of the two projects is successful, what is the probability that only the Asian project is successful? (Round your answer to three decimal places.)

b

step-by-step explanation:

the total is 23.97. 0.25% is off so you have to subtracting 25% from 100% and you will get 75% if you convert it to decimal you will get 0.75. you have to find the original because the formula is % times original = total.so you have the total and the % so you just have to plug it in.

3/4 ÷ 3/4

step-by-step explanation:

basically divide any proper fraction with itself to fit the criteria.

so if we are using 3/4, then:

3/4 ÷ 3/4 = 1

so 1 is the quotient.

and the numerators for both these fractions is 3.   and if we divide the numerators:

3 ÷ 3 = 1

we see that quotient is equal to our original quotient as well.

i think the answer is seven, for if i'm being useless °ω°

step-by-step explanation:

1.3 million hoops i believe