How do you solve 4x^2 - 8x + 4 = 0 as completing the square? Is there a solution?

1

Step-by-step explanation:

Yes, there is a solution! You first look for a common factor to factor away. Observing, you see that there is common multiple of 4, so your equation becomes . Dividing away the 4, we  get . From here, we can complete the square: which is equal to . When x=1, both sides of the equation equal 0, so x=1.

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°

7,24

step-by-step explanation: