A fair die is a cube with six sides numbered 1 to 6. Suppose a fair die is rolled 8 times. What is the probability of rolling a 3 on the die 5 times? Express your answer as a decimal rounded to 4 decimal places after the decimal point.

0.0772

Step-by-step explanation:

Probabilities are expressed by (favourable outcomes / total number of outcomes). In this problem, there is 1 favourable outcome- 3. There are also 6 total outcomes because this is a 6 sided die.

That means the outcome for rolling a 3 is equal to 1/6.

To find the probability of rolling a 3 several times, we multiply the probability of the first event by the number of times we want it to occur.

1/6 ^5 = 6/7,776 = 0.0772

This about a 8% chance

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

$4034.40

the perimeter of the field is the sum of the lengths of the four sides:

47 yd + 158 yd + 47 yd + 158 yd = 410 yd

the cost of 3 ft (1 yd) of fence is 3×$3.28 = $9.84.

so the cost of jake's wood perimeter fance is

(410 yd) × ($9.84 /yd) = $4034.40