A Washington-based nonprofit research group recently released a report indicating that 60% of government workers acknowledge witnessing violations of ethical standards, policies, or laws in the past year, 40% of which went unreported. An additional 10% of government workers acknowledged making false reports of violations of ethical standards, policies or laws when they did not actually occur. What is the probability a randomly selected government worker witnessed a violation of ethical standards, policies or laws in the past year but did not report it

The probability  that a randomly selected government worker witnessed a violation of ethical standards, policies or laws in the past year but did not report it is 0.3

Step-by-step explanation:

The outcome of the Washington- based nonprofit research group are that -

∴ P(60%) + P(10%) =  P(70) which is Probability of those that are involved in one form of violations or the other.

Therefore, P(100%) - P(70%) = 30%

P( Not committed and withnessed any violations of ethical standards, policie or law) = 30%/100%

= 0.3

(x, y)→(x − 8, y − 7)

step-by-step explanation:

enjoy!

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.